Eternity of Pagume 6

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Name of Ethiopian calendar months and name of Gregorian calendar months are unlike.

Name of Ethiopian calendar months and name of Gregorian calendar months are unlike.

Ginbot and May are unlike months.

Today is Kidamelt 10 Ginbot 2005 in the Tropics, when Saturday 18 May 2013 is in the Temperates.
The name Ginbot is different from the name May. Ginbot is a subset of Ethiopian calendar that has 30 days and it is the 9th month of the year. But May is a subset of Gregorian calendar that has 31 days and it is the 5th month of the year. Ginbot reveals 30 faster rotations of the Tropics, when May reveals 31 slower rotations of the Temperates.
Ginbot and May do not overlap. Therefore, Ginbot and May are different months, because each month has different beginning and ending days. This means that Ginbot is 1, when May is 9 and Ginbot is 30, when June is 7, and May is 31, when Ginbot is 23 in all categories. Therefore, only the first 23 days of Ginbot overlaps with the last 23 days of May.
Fig.9. shows the intersection of Ginbot and May is 23 days. n(G)=30 n(M)=31, n(GnM)=n(MnG)=23 , n(M’)=7, n(G’)=8.

Finally it is useful to know that Ginbot and May are different months according to which each month recurs during different seasons. Thus the month Ginbot recurs during two seasons of the north and south Tropics, when May does during two seasons of the north and south of Temperates. Therefore; 30 of Ginbot recur during Tsedey of north and Metsew of south Tropics respectively. When 31 days of May recur during Spring of north and Autumn of south Temperates respectively.

Ginbot and May are unlike months.

Today is Kidamelt 10 Ginbot 2005 in the Tropics, when Saturday 18 May 2013 is in the Temperates. The name Ginbot is different from the name May. Ginbot is a subset of Ethiopian calendar that has 30 days and it is the 9th month of the year. But May is a subset of Gregorian calendar that has 31 days and it is the 5th month of the year. Ginbot reveals 30 faster rotations of the Tropics, when May reveals 31 slower rotations of the Temperates. Ginbot and May do not overlap. Therefore, Ginbot and May are different months, because each month has different beginning and ending days. This means that Ginbot is 1, when May is 9 and Ginbot is 30, when June is 7, and May is 31, when Ginbot is 23 in all categories. Therefore, only the first 23 days of Ginbot overlaps with the last 23 days of May. Fig.9. shows the intersection of Ginbot and May is 23 days. n(G)=30 n(M)=31, n(GnM)=n(MnG)=23 , n(M’)=7, n(G’)=8. Finally it is useful to know that Ginbot and May are different months according to which each month recurs during different seasons. Thus the month Ginbot recurs during two seasons of the north and south Tropics, when May does during two seasons of the north and south of Temperates. Therefore; 30 of Ginbot recur during Tsedey of north and Metsew of south Tropics respectively. When 31 days of May recur during Spring of north and Autumn of south Temperates respectively.

Comparison of the false definition of Ethiopian months by the Gregorian months

Ethiopian and Gregorian calendar months are compared. Ethiopian and Gregorian calendar months are compared based on the following eight comparable and observable facts. These eight comparable observable facts are • Name of the month, • Order of the month, • Number of days the month has, • The place where the month recur, • Beginning and ending days of each moths, • Number of days of the overlapping months (intersection of the months), • Name of the season during which the month recurs. The name Miyazia is different from the name April. Miyazia is a subset of Ethiopian calendar that has 30 days and the 8th month. But April is a subset of Gregorian calendar that has 30 days and it is the 4th month. Miyazia reveals 30 faster rotations of the Tropics, whereas, April is 30 slower rotations of the Temperates. Although each of Miyazia and April has the same number of 30 days, they do not overlap. Therefore, Miyazia and April are different months, because each month has different beginning and ending days. This means that Miyazia is 1, when April is 9 and Miyazia is 30, when May is 9, and April is 30, when Miyazia is 22. Therefore, only the first 22 days of Miyazia overlaps with the last 22 days of April. Finally it is useful to know that Miyazia and April are different months according to which each month recurs during different seasons. Thus the month Miyazia recurs during the third quarter season of the north and south Tropics, when April does during the third quarter season of the north and south Temperates. Therefore; 30 days of Miyazia recur during Tseday of north and Metsew of south Tropics; when 30 days of April recur during Spring of north and Autumn of south Temperates respectively.

Linear Equation of Pagume 6

Linear Equation of Pagume 6 Pagume 6 The day Pagume 6 recurs once in every four years. This means that one day of Pagume 6 corresponds with 4 years, 2 days of Pagume 6 corresponds with 8 years, 3 days of Pagume 6 with 12 years, 4 days of Pagume 6 with 12 years. Therefore there are perfect relationships between the number of day of Pagume 6 and the number of years. This means that for each value of year there is corresponding value of Pagume 6. Suppose the independent variable year is x and dependent variable Pagume 6 is y. The general linear equation of Pagume 6 y=f(x)---------------------(1) The general form of linear equation of Pagume 6 is written as follows y=a+bx---------------------(2) Where the variable y is number of days of Pagume 6 and the independent variable x is the number of years. The constant a is the intercept of Pagume 6, i.e. value of Pagume 6 when year is zero and coefficient b is the slope of the Pagume line that measures by what number of hours the day Pagume 6 changes when the year changes by a unit. We can make the exact linear function of Pagume 6 by obtaining the value of constant a and coefficient b from two points. Let the coordinates of the first and second points of Pagume 6 be (4,1) and (12,3) respectively. The first point coordinate (4,1) states that when year x is 4 the corresponding day of Pagume 6 y is 1. The second point coordinate (12,3) states that when year x is 12 the corresponding day of Pagume 6 y is 3. Thus when year changes from 4 to 12 the day Pagume 6 also changes from 1 to 3. Let change x is denoted Δx=x2-x1 and change y by Δy=y2-y1. The coefficient b is the slope determined by dividing change y by change x. Δy/Δx=(y2-y1)/(x2-x1)---------------------(2) Δy/Δx=(3-1)/(12-4)=2/8=1/4=0.25------------------(3) Substitute the number 0.25 for the coefficient b in equation (2). y=a+0.25x---------------------(4) The next step is determining the constant a. by substituting value of two pints in equation (2) and solving simultaneously. 1=a+b4---------------------(2.1) 3=a+b12---------------------(2.2) We know that b=0.25 and substitute in either equation 2.1 or 2.2 and solve for a 1=a+0.25*4---------------------(5) 1-1=a+1-1---------------------(6) a=0---------------------------(7) Linear equation of Pagume 6 is determined by substituting result of equation 7 in 4. y=0+0.25x---------------------(8) y=0.25x-----------------------(9) y=0.25x y -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 x -28 -24 -20 -16 -12 -8 -4 4 8 12 16 20 24 28 Linear Equation of Pagume 6 y=0.25x---------------------(1) Prediction of the day Pagume 6 Linear equation of Pagume is used for prediction. For example, Ethiopia celebrated the African millennium in the year 2000. That was done based on the Tropical calendar of Ethiopia. If we ask how many year, months, days and hours of Pagume 6 are in 2000 years? Alternatively show those 500 days of Pagume 6 is equal one year, 4 months, 12 days and 18 hours in 2000 years. Illustration Step 1: Determining Year of Pagume 6 Substitute number 2000 in x in equation (1) .Thus, equation (2) shows there are 500 days of Pagume 6 in 2000 years, and it is obtained when we multiply ¼ by 2000: y=0.25*2000=500 days------------------(2) We must convert 500 days into unit of year. Thus, if 365.25 days is equal to year, 500 days is how many years? 500 days divided by 365.25 days multiplied by 1 year is shown in equation 3. y= (500 days)/(365.25 days)*year--------------------(3) y=1.36892539335 year------------------(4) Equation (4) states that there is 1.36892539335 year of Pagume 6 in 2000 years Determining year of Pagume 6 is the integer element of equation (4). Year of Pagume 6=1.36892539335 year-0.36892539335 year-------(5) Year of Pagume 6=1------------------------(6) Equation (6) states year of Pagume 6 is one year. But equation (4) minus equation (6) yields a fraction year of Pagume 6. y=0.36892539335 year------------------(7) Equation (7) states that a fraction 0.36892539335 year of Pagume 6 and less than unit of year and ready to be converted into the next unit is called month of Pagume 6 in step 2 below. Step 2: Determining month of Pagume 6 To determine unit of month from equation (7), first we must convert fraction year of equation (7) into day’s unit. If one year is equal to 365.25 days, 0.36892539335 year of Pagume 6 is equal to how many days? y=(365.25 days)/(1 year)*0.36892539335 year=134.5 days----(8) Second to convert 134.25 days of Pagume 6 into unit of month, we need to determine the average number of days of the month in the solar year. There are 365.25 days and 12 months in a solar year. An average number of days of the month is 30.4375 days (=365.25 days divided by 12 months) shown in equation (9). Average number of days of a month =(365.25 days)/(12 months)=30.4375 days----(9) Third using equations (8) and (9) we pose the question that if one month has 30.4375 days, 134.5 days of Pagume 6 is equal to how many months? An average number of months of Pagume 6 are about 4.41889 month. Number of month of Pagume 6=(134.5 days)/(30.4375 days)=4.41889 month----(9) Determining the month of Pagume 6 means the integer elements of equation (9) and it is 4 months. Equation (9) minus 4 is equal to fraction month of equation (10), Month of Pagume 6=4.41889-0.41889--------------(10) Month of Pagume 6=4-----------------------(11) Equation (11) states number of month of Pagume 6 is 4. But equation (9) minus equation (11) yields a fraction month of Pagume 6. Month of Pagume 6=0.41889--------------------(12) Equation (12) states that a fraction 0.41889 month of Pagume 6 and less than unit of month and ready to be converted into the next unit is called days of Pagume 6 in step 3 below. Step 3: Determining number of days of Pagume 6 Unit of 0.41889 month of Pagume 6 is converted into unit of days of Pagume 6. Therefore,12.75 days of Pagume 6 is obtained by calculating that if one month is equal to 30.4375 days, 0.41889 month is equal to how many days? Average number of days =(0.41889 month)/(1 month)*30.4375 days=12.75 ----(13) Number of days of Pagume 6=12.75-0.75-------------------(14) Number of days of Pagume 6=12------------------------(15) Equation (15) states number of days of Pagume 6 is 12. But equation (13) minus equation (15) yields a fraction days of Pagume 6 in equation (16). Fraction of days =12.75-12=0.75------------------(16) Equation (16) states that a fraction 0.75 days of Pagume 6 and less than unit of day and ready to be converted into the next unit is called hours of Pagume 6 in step 4 below. Step 4: Determining number of hours of Pagume 6 We convert a fraction of days into an integer hour’s unit. Therefore, if one day is 24 hours, 0.75 days is equal to how many hours? Average number of hours of Pagume 6=(0.75 days)/(1 day)*24 hours=18 ----(17) Number of hours of Pagume 6=18 ---------------(18) Equation (18) States there are 18 hours of Pagume 6. Recall the question how many year, months, days and hours of Pagume 6 are in 2000 years? Collecting results of steps 1 to 4 or equations (6), (11), (15) and (18) and read as there are one year, 4 months, 12 days and 18 hours of Pagume 6 in 2000 years.

Meskeram of the tropics is different from September of the temperates.

Meskeram of the tropics is different from September of the temperates.

·         Meskeram and September months are compared  based on the following  comparable and observable facts:

Name of the month,    http://g9h8i7.wordpress.com

·         Order of the month,

·         Number of days the month has,

·         The place where the month recur,

·         Beginning and ending days of each moths,

·         Number of days of the overlapping months (intersection of the months),

·         Name of the season during which the month recurs.

                                                                                

The name Meskeram is different from the name September. Meskeram is a subset of Ethiopian calendar that has 30 days and the 1^st month. But September is a subset of Gregorian calendar that has 30 days and it is the 9^th month. Meskeram reveals 30 faster rotations of the Tropics, whereas, September is 30 slower rotations of the Temperates.

Although each of Meskeram and September has the same number of 30 days, they do not overlap. Therefore, Meskeram and September are different months, because each month has different beginning and ending days. This means that Meskeram is 1, when September is 12 and Meskeram is 30, when October is 11, and September is 30, when Meskeram is 19 in category year one. Moreover, Meskeram is 1, when September is 11 and Meskeram is 30, when October is 10, and September is 30, when Meskeram is 20 in category year two and three respectively. Therefore, only the first 19 and 20 days of Meskeram overlaps with the last 19 and 20 days of September in category one and others respectively.

The intersection of Meskeram and September is 19 days in category one and 20 days in category two. n(M)= n(S)=30, n(MnS)=n(SnM)=19 or 20, n(M’)=n(S’)=11or 10.